Question

Consider the line that passes through the point (3, -6) and has a slope of 4.

Part 1: Write the equation of this line using point-slope form.
Part 2: Using your equation from part 1, rewrite this equation in slope-intercept form. Make sure to show all of your work.
Part 3: Using your equation from part 2, rewrite this equation in standard form. Make sure to show all of your work.

Answer 1

Can you do the parts one at a time please.

Answer 2

p1 you read my mind :) one at time
y-y1=m(x-x1) is your formula for point slope form
-6-y1=4(3-x1) i think that is all for p1

Answer 3

Okay I understand that part.

Answer 4

okey then now p2

Answer 5

p2

take -6-y1=4(3-x1) and solve for y basicaly that is what is meant by slope intercecpt form y=mx+b

-6-y1=4(3-x1) sfy

Answer 6

Minus the 6 from each side?

Answer 7

yup

Answer 8

-6-y1=4(3-x1) sfy

actuall it is add the 6 since it is -
NOTE you can change the name of variable at anytime so lets call y1 y and x1 x
-y=-1*(4(3-x) +6) mult by -1

y=-4(3-x)-6 distribute -1
y=-12+4x-6 distubute 4
y=-18+4x add like terms 12 and -6
y=4x-18 rearrange
THat is part 2

Answer 9

part 3 equation is like
ax+by=c
y=4x-18

18= 4x- y <
c = ax- y


I think that is right