Question

Help please :)

Answer 1

with? ;o

Answer 2

the answer is 13

Answer 3

^ that lol :3

Answer 4

haha zz shush

Answer 5

:)

Answer 6

:P

Answer 7

So basically in an elimination you're going to just look at both equations and see what you can easily get for them to have something in common. So if you multiply both sides of the bottom equation by -2 you see that you get -2x^2+2y^2=-3.

Why did I multiply that by -2? Well up in the other equation you see it has 2x^2 so now if I add both the left sides together and add the right sides of both equations together it cancels out the x^2 and just leaves you with y^2!

Answer 8

But there is 4 solutions? @Kainui

Answer 9

There are 4 solutions I suppose because when you take the square root of a number you end up with a negative and a positive answer.

Answer 10

so so square root y^2....then square root it.. then y^2 and - y^2?

Answer 11

you*

Answer 12

@nitz what would be my final answer? o.0

Answer 13

wait i will tell

Answer 14

ok

Answer 15

note: there will be 4 answers

Answer 16

so the answers are
(sqrt(5/2),1)
(-(sqrt(5/2)),1)

Answer 17

(sqrt(21/2),-3)
(-(sqrt(21/2)),-3)

Answer 18

is that what order they go in ?

Answer 19

order ill check

Answer 20

first is ((-sqrt(21/2)),-3)
second is ((-sqrt(5/2)),1)
third is (sqrt(5/2),1)
fourth is (sqrt(21/2),-3)

Answer 21

Thank you so much! Its correct :D

Answer 22

welcome

Answer 23

so will you be my friend?

Answer 24

Yes, of course :)

Answer 25

so any other question ?

Answer 26

Do you understand how to solve this?

Answer 27

@nitz ?

Answer 28

wait i m checking

Answer 29

ok sorry

Answer 30

i am not getting so sorry..

Answer 31

2x^2+4y=9 ............1
x^2-y^2=3/2 ..........2

squaring equation 2,
2x^2-2y^2=3 ..........3

and substracting 3 from 1,we get
4y+2y^2=6


and then factorise the above equation

2y^2+4y-6=0
2y^2+6y-2y-6=0

y=1,-3