Question

(Coordinate Geometry)
Write the equation of the circle in standard form with center and radius given.

Center (8, 0), radius = √3

Answer 1

(8-x)^2 + (0-y)^2 = sqrt(3)^2
(8-x)^2 = y^2 = 3

Answer 2

HOW DO U DO IT? CAN U EXPLAIN IT BRIEFLY???

Answer 3

are you asking me or him sradha?

Answer 4

U

Answer 5

\[\frac{(x-8)^2}{3}+\frac{y^2}{3}=1\]

Answer 6

(x_1 - x)^2 + (y_1-y)^2 = r^2 where (x_1,y_1) is the point givin

Answer 7

it's just pythagorean theorem on a little crack:)

Answer 8

OK