Question

use elimination to slove this system of equations.
3y=2x+1
-6y=-6x-12

A.(7,5)
B.(-5,7)
C.(5,7)
D.(7,6)

Answer 1

y = 2x + 1 / 3 plug in second equation

Answer 2

that would be substitution, not elimination

Answer 3

ohh oops sorry dont rememebr the methods name

Answer 4

yeah, the names are weak in my opinion...

to use elimination, multiply the first equation by 2 and add it to the second. that will "eliminate" y

Answer 5

i got a weird answer.

Answer 6

can you show me what you got after just the first step I said?

Answer 7

6y=4x+22

-6y=-6x-12

Answer 8

ok, now add those two equations together
what do you get?

Answer 9

-2x+10?

Answer 10

oh you have an extra 2 in there, should be

6y=4x+2

-6y=-6x-12

unless there was a typo in your original post
which is it?

Answer 11

extra 2

Answer 12

6y=4x+2
or
6y=4x+22

???

Answer 13

what are your two original equations again?

Answer 14

i got 6y=4x+22

3y=2x+1 -6y=-6x-12 are the original

Answer 15

ok, so multiplying the first equation by 2 how do you get 22 ?

Answer 16

multiply the first equation by 2 and you get
2(3y=2x+1)
^^^^
simplify, what do you get?

Answer 17

-2x+3y=1
6x-6y=-12
6(-2x+3y=1)
-2(6x-6y=-12)
=-12x+18y=6 ----- i
and -12x+12y=-24 -----ii
subtractin i and ii
we get 6y=30
therefore y=30/6=5
putting y=5 in -2x+3y=1
we get -2x+15=1
x=14/-2
therefore x=-7
ans. (-7,5)