I'm stuck, please help :P (there's a picture with the proper equation format in the discussion post below)

Question

anonymous · Answer

attachment

anonymous · Answer

I've got sinA = 5/13 cosA = 12/13 sinB = 8/17 and cosB = 15/17

anonymous · Answer

alright you hae restrictions 0<=A<=90 for cos(A) what does this tell you about what sign cos is

anonymous · Answer

Does it mean that cos will be positive? This is the part that throws me off

anonymous · Answer

yes it means that cos(A) is positive

anonymous · Answer

Awesome, so cos(A) = 12/13 is correct?

anonymous · Answer

90<=B<=180

anonymous · Answer

yes

anonymous · Answer

now what is Sin(accounts to y variable) when it's between 90-180

anonymous · Answer

Would it also still be positive because sincose is positive in the second quadrant?

anonymous · Answer

yes sin is positive cos is negative in the 2nd due to it being the x values

anonymous · Answer

Oh, so cos(B) would = (-15/17)?

anonymous · Answer

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