Question

Determine the missing coordinates of the points on the graph of the function.

Answer 1

what's \(\Large \tan \left( -\frac \pi 6 \right)\) and \(\Large \arctan \left( -\sqrt3 \right)\) ?

Answer 2

-1/sqrt(3) and -pi/3?

Answer 3

so that's all I needed to do huh?

Answer 4

yeah
-sqrt(3)/3 & -pi/3

Answer 5

π/4 doesn't give an approximation :(

Answer 6

π/4??

Answer 7

0.66577 so 0.666 dun dun dun :P

Answer 8

π/4 is at the top.

Answer 9

tan pi/4 is exactly 1

Answer 10

oh okay I did arctan, why did we use tan for 1 and arctan for the other?

Answer 11

\[\Large y=\arctan (x)\]\[\Large \implies x=\tan(y)\]

depends, whether you are trying to find \(x\) or \(y\) co-ordinate...

Answer 12

yeah gotcha, I thought they were all x's, but the last one wasn't, thus arctan, thanks :D