two numbers have a difference of 20. Find the numbers if the sum of their squares is a minimum value.
x-y=20 x^2 + y^2 =?

Question

two numbers have a difference of 20. Find the numbers if the sum of their squares is a minimum value.
x-y=20   x^2 + y^2 =?

zzr0ck3r · Answer

is this for calc?

anonymous · Answer

functions

zzr0ck3r · Answer

im confused by the question, find the numbers if the sum of their squares is a min value? thats exactly what it says?

anonymous · Answer

yea it just means you have to complete the square to get the vertex, which is the two numbers

zzr0ck3r · Answer

sorry I messed up

zzr0ck3r · Answer

(y+20)^2 + y^2 = 2y^2 + 40y + 400 = 0 = y^2 + 20y + 200 = 0
(y+10)^2= 200
y = +- 10sqrt(100)-10

zzr0ck3r · Answer

errrrrr
y = +- 10sqrt(2)-10 sorry

zzr0ck3r · Answer

I dont think you need to complete the square to get the virtex but I did it just in case you needed it

anonymous · Answer

thanks alot!

zzr0ck3r · Answer

I forget the virtex formula something like -a/2b?

zzr0ck3r · Answer

vertex*

zzr0ck3r · Answer

-b/2a so -20/2 = -10

anonymous · Answer

yeah the answer in the textbook was +/-10

zzr0ck3r · Answer

word yeah the +- from completeing the square i c