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simplifying trig functions
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???
you could study simplifing trig functions for 20 years and not be done:) be more spacific
f(x) = cos (x/2) f(3pi/2)=
they say its sqrt2/2 but i dont know how they get that
rate of change is what i need it for
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well cos((3pi/2/2) = cos(3pi/4) = -sqrt(2)/2 from the unit circle...they are wrong:)
note 1/sqrt(2) = sqrt(2)/2
1/sqrt(a) = sqrt(a)/a more general
thanks
\[f(3\pi/2)=\cos (3\pi/2)\] \[f(3\pi/2)=\cos (\pi+\pi/2)\] \[f(3\pi/2)=-\cos (\pi/2)\] \[f(3\pi/2)=-1/\sqrt{2}\]
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