Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

simplifying trig functions

OpenStudy (anonymous):

???

OpenStudy (zzr0ck3r):

you could study simplifing trig functions for 20 years and not be done:) be more spacific

OpenStudy (anonymous):

f(x) = cos (x/2) f(3pi/2)=

OpenStudy (anonymous):

they say its sqrt2/2 but i dont know how they get that

OpenStudy (anonymous):

rate of change is what i need it for

OpenStudy (zzr0ck3r):

well cos((3pi/2/2) = cos(3pi/4) = -sqrt(2)/2 from the unit circle...they are wrong:)

OpenStudy (zzr0ck3r):

note 1/sqrt(2) = sqrt(2)/2

OpenStudy (zzr0ck3r):

1/sqrt(a) = sqrt(a)/a more general

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

\[f(3\pi/2)=\cos (3\pi/2)\] \[f(3\pi/2)=\cos (\pi+\pi/2)\] \[f(3\pi/2)=-\cos (\pi/2)\] \[f(3\pi/2)=-1/\sqrt{2}\]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!