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Mathematics 22 Online
OpenStudy (anonymous):

I am lost it says to factor completely. Remember to look first for a common factor and to check by multiplying. If a polynomial is prime, state this. 20x^2 + 100x + 125

OpenStudy (anonymous):

20x^2 + 100x + 125 5(2x + 5)(2x + 5) 5(2x + 5)^2

OpenStudy (anonymous):

what was the common factor ? and how do i go about looking for it?

OpenStudy (anonymous):

how do i go about checking it?

OpenStudy (asnaseer):

you might find this site helpful: http://www.mathsisfun.com/algebra/factoring-quadratics.html

OpenStudy (phi):

You can check it by multiplying it back out to get the original expression. It is good practice: (2x+5)*(2x+5)= 2x*2x+2x*5+5*2x+5*5 (using FOIL) you can finish it off... also, you can user wolfram, http://www.wolframalpha.com/input/?i=++++factor++20x%5E2+%2B+100x+%2B+125

OpenStudy (anonymous):

@phi using wolframalpha should never be a solution.

OpenStudy (anonymous):

First expand each part to look for common factors as the question states: \[2 * 2 * 5 * X^{2} + 2*2*5*5*x + 5*5*5\] Then you can solve.

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