What is the equation of the line that passes through the point (3, 2) and has a slope of 4?

y = 4x - 1

y = 4x - 5

y = 4x - 10

y = 4x + 1

Question

What is the equation of the line that passes through the point (3, 2) and has a slope of 4?

y = 4x - 1

y = 4x - 5

y = 4x - 10

y = 4x + 1

anonymous · Answer

here we go again right?

anonymous · Answer

Yes. I know>.< I forgot AGAIN.

anonymous · Answer

once more it is the point- slope formula 
$$y-y_1=m(x-x_1)$$ make a direct substitution with the numbers you have

anonymous · Answer

that is $x_1=3,y_1=2,m=4$ let me know what you get

anonymous · Answer

write it on your keds before the test

anonymous · Answer

keds?

anonymous · Answer

general form of the line is y=mx+c,
m is the slope and c is the y-intercept
since you are given that m=4,apply it to the equation gives you y=4x+c
since (3,2) is on the line,substitute into the equation gives you,
3=4(2)+c
.'. c=-5
.'. y=4x-5