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Use the substitution method to find the solutions to the systems of equations Y=-x^2 Y=x Please help got to do today
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x= o and -1
How did you get that
we have y=x=-x^2
or simply x=-x^2
shift everything to LHS, so x^2 +x=0
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take x common so the equation is x(x+1)=0 now the product of two numbers( x nd (x+1)) is 0, so either one of them can be equal to 0
so this implies either x=0 or x+1=0 solving both we get x= 0 and -1
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