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Mathematics 23 Online
OpenStudy (anonymous):

factor. x^2-3xy+2y^2

OpenStudy (anonymous):

not too many choices if it is going to factor are there?

OpenStudy (anonymous):

that didn't really make sense?...sorry

OpenStudy (anonymous):

first terms have to be \(x\) and last term can be either \(2y\) and \(y\) or \(-2y\) and \(-y\)

OpenStudy (anonymous):

since the product of the first terms must be \(x^2\) and the product of the last terms has to be \(2y^2\) so your only choices are \[(x+2y)(x+y)\] or \[(x-2y)(x-y)\] that is it. then check to see which one is right, i.e. which one gives you \[x^2-3xy+y^2\] when you multiply out

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