factor. 3x^2-5x-12
(x-3)(x+(4/3))
??
(3x-4 )(x+3 )
can you explain the steps..
sir actually what we get after factorising are the two roots of the equation( those values of x which makes the value of function equal to zero), so our objective to factorise is indirrectly to find the roots of the equation . u following till now?
there is a formula for finding the roots of a quadratic equation, use that to get the roots of this equation. suppose the roots come to be x=h nd x=j, then the equation will be, (x-h)(x-j) :)
yeah I know how to factor normal ones, but this one is complicated. you have to find two numbers that multiply to c and add to b, but for this one, it's a little different.
the quadratic formula is a fool proof way to factorise( also know as shri dharacharya formula, given by an indian):) u know the formula right?
try to find those 2no. which has a product=3*12=36, and have a difference between them=5. we have, 36=1*36 36=2*18 36=3*12 36=4*9 ----------->here, we have a difference of 5 between the no.(irrespective of signs) 3x2−5x−12 3x2−9x+4x−12 (writing -5 as sum of -9 and 4) Take out common value from any two groups [3x2−9x][+4x−12] 3x(x−3)3(+x−3) = (3x+3)(x−3)
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