Question

6x^2-12x=0

Answer 1

hi juniors mom,

are you looking for the roots of x?

Answer 2

pull out a 6x, and try to solve

Answer 3

quadratic equations.

Answer 4

X = -b\[x = -b \pm \sqrt{b ^{2}-4(a)(c)}\div2(a)\]

Answer 5

why bother with quadratics?

Answer 6

Ignore that first x = -b >_<

Answer 7

6x^2-12x=0
6x(x-2)=0
x1=0
x2=2

Answer 8

First divide both sides by 6:
6x^2-12x=0 =====> x^2-2x=0
Then, factor our the x===> x(x-2)=0
Then you use the property that when you multiply two numbers and get zero
either one of the numbers is zero or both of them are zero.

So you have x is one of the numbers so x=0
OR the other number x-2=0 ===> x=2 (adding 2 to both sides)
solution: x=0 or 2

Answer 9

6x^2-12x=0
6x^2=12x
x=12/6=2