Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

These graphs are my worst enemy -.- May someone please explain to me or show me step by step how to find the answer so I know what to do in the future? Picture is in the attachment.

OpenStudy (anonymous):

OpenStudy (anonymous):

I never really understood how to find asymptotes

OpenStudy (anonymous):

@terenzreignz If you have the time, do you think you could help me on this one? (: I understand if not.

terenzreignz (terenzreignz):

I'm sorry I was answering another question, would you like to show me your new question?

OpenStudy (anonymous):

It's all good (: And yes please, if you don't mind.

terenzreignz (terenzreignz):

you know what asymptote means?

OpenStudy (anonymous):

I was just about to ask Lol. I don't know what it is or means.

terenzreignz (terenzreignz):

An asymptote is (more or less) a line that the graph seems to approach, but NEVER touches. For example, the line x = 2pi the graph seems to get closer and closer to it, but never really touches it, you get me? :)

OpenStudy (anonymous):

Oh, okay I see (:

terenzreignz (terenzreignz):

Well, can you name another asymptote?

OpenStudy (anonymous):

Well I see 2pi and -2pi, or do you mean a completely different asymptote?

terenzreignz (terenzreignz):

-2pi is a different asymptote :) so as you see, each asymptote is 2pi plus 2npi, where n is an integer :) take -2pi, for instance, in that case, n = -1 Get it? :)

OpenStudy (anonymous):

OOOH! Lol So simple (:

terenzreignz (terenzreignz):

haha, it just looks tough :)

OpenStudy (anonymous):

Definately Lol Would it be 4pi(n)? I see there's no 2pi(n) :o

OpenStudy (anonymous):

terenzreignz (terenzreignz):

I think I'd go for the third one. I don't know why it isn't in the choices, though

OpenStudy (anonymous):

hmmm, alrighty (: Thank you again, btw (:

terenzreignz (terenzreignz):

No problem :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!