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Find the nth term of the geometric sequence with first term -2 and common ratio 1/3.
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nth term = a r^(n-1) where a=first term and r = common ratio
ok let me try
what is a? @cwrw238
first term = -2
so a1?
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I have -2 * 1/3^(n-1)
but what is n?
yes first term is sometimes referred to as first term
as a1!
what is n in my equation above
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you asked for the nth term - n is any term
So what do I plug in there??
I have -2 * 1/3^(n-1) this is what i have, how to solve?
your answer is correct -2*(1/3)^(n-1)
thats it - thats the formula for the nth term
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are u sure that is all I put?
for example if you need the sec ond term it is -2*(1/3)^(2-1) replacing n by 2
= -2 * 1/3 = -2/3
yes - i'm sure
so my final answer is -2*(1/3)^(n-1) ?
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