Question

Solve the following system using the substitution method.
x-3y=-5
5x+6y=-19

Answer 1

can you solve for x in the first equation?

Answer 2

after you do that, plug that expression in for x into the second equation...

Answer 3

x=3y-5 ?

Answer 4

good now substitute that expression in for x into the second equation:

5x + 6y = -19
5(3y-5) + 6y = -19

can you solve from here?

Answer 5

x=-5+3y;
5(-5+3y)+6y=-19;
-25+15y+6y=-19;
21y=6;
y=6/21...

Answer 6

That's as far as i got ..

Answer 7

use that value for y in the first equation to know x

Answer 8

ok... do you see the post right above^^^ ? that answer is correct for y... all you need to do is use that value for y=6/21 and plug that back into any equation you started with to find the value for x...

Answer 9

x=-4.1428
y=0.285714

Answer 10

Im sooooo lost right now ! This is what my answer options are..

Answer 11

x=-5+3y now put this in other equation and solve for y!

Answer 12

once u got the y value put it back in x-3y=-5 and solve for x.

Answer 13

5x+6y=-19
5(-5-3y)+6y=-19
-25-15y+6y=-19
-9y=6
y=-6/9
y=-2/3
u made the mistake in ur question.. its x+3y=-5* not x-3y=-5

Answer 14

now to solve for x put y=-2/3 in x+3y=-5
x+3(-2/3)=-5
x-2=-5
x=-5+2
x=-3
so its option 1!!