It was 41 degress F at 8:00 am and 69 degrees F at 4:00 pm If the temperature rose at a constant rate what was the temperature at 1:00 pm?

Question

anonymous · Answer

Convert 4pm to 16am and 1pm to 13am.
m= (69-41)/(16-8) = 28/8 = 7/2
(x-41)/(13-8) = 7/2
2(x-41) = 7(5)
2x - 82 = 35
2x = 117
x = 58.5 degrees F

anonymous · Answer

I don't understand the conversion of the time and where that comes from

shane_b · Answer

(Fix..though it was at 2pm!)

The temperature went up 28 degrees in 8 hours changing at a constant rate...so the ratio is:
$$\frac{28}{8}=\frac{x}{5}$$
Solve for x to get a +17.5 degree increase. 41+17.5 = 58.5F.

shane_b · Answer

You don't need to bother with the time conversion if you just think about how many hours are between 8am and 4pm, and 8am and 1pm.

shane_b · Answer

He was just converting it to military time...so 4pm is 1600...8am = 0800...etc. It makes it slightly easier to figure out the hours between two times.

anonymous · Answer

Thanks