Question

Help solve using quadratic equation: y=5x^2+5x-5

Answer 1

please help...

Answer 2

the quadratic formula is:
\[x = (-b \pm \sqrt{b^2 - 4ac}) / 2a\]

looking at your polynomial, you can tell that a = 5, b = 5, and c = -5

so plug that into the formula.

Answer 3

so there are 5x^2 +5x -5 =y ,than for you solve it make equal zero,like
5x^2 +5x -5 =0 divide both sides by 5 and will get
x^2 +x -1 =0
discriminant D=1+4=5

so than those roots x_1 and x_2 =(-1+/- sqrt5)/2 =(1+/-sqrt5)/2

x_1 = (1-sqrt5)/2
x_2 =(1+sqrt5)/2

hope so much that is understandably sure ,right

good luck

bye