Question

The area (in sq. units) of the region bounded by the lines 2x − y + 2 = 0, 2x + y − 2 = 0 and the x-axis is

Answer 1

I can walk you through this one, you ready? :)

Answer 2

yup

Answer 3

The only tricky part about this is to set up the definite integral. :)
So, it helps to have a mental picture (if not an actual drawing) of that which you're finding the area...
Do you have one?

Answer 4

hmm nop..not in question..

Answer 5

Ok, well, you have to have an idea of what your graph looks like :)
It might help to write the equations in this form
y = mx + b

Answer 6

hmm

Answer 7

You're overthinking this far too much, @terenzreignz.
@nikita02, graph both of the lines by their y = mx + b form and come up with the simplest solution you can find.

Answer 8

The options are .. A. 1/2 B. 1 C.2 D. 4
Could come up with a possible solution to this question ..

Answer 9

For sure, yes, but wouldn't you rather arrive at the answer yourself, with but a little help? :)

Answer 10

find where each function intersects the x axis and those are your intervals [a,b] for the definite integral.

Answer 11

@terenzreignz yup ur right :)

Answer 12

@baldymcgee6: I wouldn't think that necessary, seeing as the area is a triangle...
Form the triangle, and you'll immediately see a few answers that are incorrect because of the dimensions of that area.

Answer 13

@quantumModulus: right, it is simply a triangle.

Answer 14

@QuantumModulus
You're right, it is a triangle, and by using distance formula, you can certainly get the area...
@nikita02
Does this question stem from an algebra test, or a calculus test?

Answer 15

@nikita02: if you can't use your imagination, here's a quick plot http://www.wolframalpha.com/input/?i=graph+y%3D2x%2B2+and+y%3D-2x%2B2

Answer 16

you will see exactly what we are talking about, it is simply a triangle, and there is no need for integration.

Answer 17

@baldymcgee6 thanks for the plot.. got ur point !

Answer 18

Just a quick note, though, it still pays to know how to get the area by integration, in case you get those bounded areas with curved boundaries, etc
The areas of which cannot readily be determined by known formulas :)

Answer 19

@terenzreignz okies tnks .. this ws a serious help :)