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Please help Q5, Equation of all straight lines with algebraic sum of the intercepts fixed as k..
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lets say y intercept = c so x intercept becomes : k-c because their sum must equal to k. got it so far ?
so, y-(k-c)=mx+c? is this correct?
not exactly..
lets draw a picture
um, how is it?
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|dw:1340432763552:dw|
u see, it goes through two points (0,c) and (k-c, 0) now use the equation for a line going through two points (x1, y1) , (x2, y2) \[ y-y1 = \frac{y2-y1}{x2-x1}(x-x1)\] \[ y-c = \frac{0-c}{k-c-0}(x-0)\] \[ y-c = \frac{c}{c-k}(x)\]
you can keep the equation as it is. it should be ok. or else you can try simplifying further..
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