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A SUPA SHORT TUTORIAL. Show that the product of two squares is another square.
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This is based on the identity \(a^n \cdot b^n = (a \cdot b)^n\) Take one integer as a, and the other integer as b. The two perfect squares would be in the form - \(a^2\) and \(b^2\). \( \color{Black}{\Rightarrow a^2 \cdot b^2 }\) Simplifying: \( \color{Black}{\Rightarrow (a \cdot b)^2}\) Hence proved.
Very elegant and should be most obvious to the casual observer, but I have never thought of it.
Thank you sir!
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