I am trying to think of some tricky linear or quadratic equation problems (the "solve for x" problem sets, no imaginary roots please) for a group of minors. Have any ideas?

Question

nenadmatematika · Answer

X^2-5X+6=0 :D

anonymous · Answer

That is too easy

turingtest · Answer

work backwards, what do you want the roots to be? whatever a and b they are you can make the equation from $$(x-a)(x-b)=0$$

turingtest · Answer

classics also include things with hidden quadratics, like$$ax^{2n}+bx^n+c=0$$which is quadratic in $x^n$ or$$an^{2x}+bn^x+c=0$$which is quadratic in $n^x$