Question

I have another math problem that I need help with and I thank those that are helping me I have been trying to get the concept of this for 5 hours and this is my first time using this, thenext one is -(z+9)+(4z+1)=-2(z+1)

Answer 1

first we want to get rid of the parentheses
remember that \[-(a+b)\]is like\[-1(a+b)=-a-b\]and\[+(a+b)=+1(a+b)=a+b\]so try writing the left side without parentheses

Answer 2

I still need help with it I just don't understand

Answer 3

^ @TuringTest is right.

Also, +(4z+1) is just 4z+1.

-(z+9)+(4z+1)=-2(z+1)

So, with what they said, you can rewrite this as so:

-1(z+9)+(4z+1)=-2(z+1)
z(-1) + (9)(-1) + 4z + 1 = z(-2) + 1(-2)
-z - 9 + 4z + 1 = -2z -2
___ ~~ ___ ~~~

Now, you can collect like terms here. Combine the normal numbers with the normal numbers and the numbers with z's with numbers with z's.

-z - 9 + 4z + 1 = -2z -2
3z - 8 = -2z - 2

Now, add 2z to both sides.

5z - 8 = -2

Now, add 8 to both sides.

5z = 6

Can you tell me what z is?

Answer 4

I'm still trying to understand it I don't know what Z is where do you get the other -1 from after the 9

Answer 5

thats not it

Answer 6

When you distribute, the -1 multiplies to both the z and the 9