Question

Simplify: 9x^3+6x^2+3x
divided by
3x

Answer 1

\[\frac {9x^3+6x^2+3x}{3x}=\frac {9x^3}{3x}+\frac{6x^2}{3x}+\frac{3x}{3x}\]Do you know how to divide exponents?

Answer 2

if your dividing exponents aren't you supposed to subtract them?

Answer 3

Exactly. Divide the coefficients normally and subtract the exponents.

Answer 4

3x^2+2x+1 ?

Answer 5

Perfect :)

Answer 6

awesome thanks

Answer 7

yw, good luck!