Question

In △PQR, QS is an altitude. Solve for x and y.

Answer 1

x=√78; y=6
x=6; y=3√13
x=6; y=2√6
x=2; y=6√2

Answer 2

@hang254 do you know Pythagoras theorem?

Answer 3

yes. a^2+b^2=c^2

Answer 4

Remember the geometric means?
\[\frac 4x = \frac x9\]\[\frac9y = \frac{y}{13}\]

Answer 5

Yes, i do

Answer 6

JUst solve the proportions that I set up.

Answer 7

Ok

Answer 8

x=36, y=10.816

Answer 9

For x:
\[x^{2} = 36\]\[x = 6\]
For y:
\[y^{2} = 117\]\[y = 3\sqrt{13}\]

Answer 10

Oh, thanks. I just realized that i didnt square the 36.

Answer 11

Alright. No Problem