Find an angle T on the unit circle such that 90º < T < 360º, tan T = tan U, and M angleU =81º.
a. 261°
b. 94°
c. 99°
d. 279°
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OpenStudy (anonymous):
are you getting the question?
OpenStudy (anonymous):
a?
OpenStudy (anonymous):
261
OpenStudy (anonymous):
are you sure? : / what do you think mertsj
OpenStudy (anonymous):
well yes i am surre
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OpenStudy (anonymous):
tan 81 is positive, so our tanT will have to lie in 3rd quadrant to be positive
OpenStudy (mertsj):
We know that the tangent of 81 degrees is positive so the angle must be in the third quadrant since the tangent is only positive in Quadrants I and III and it can't be in one since the requirement is that it be greater than 90.
So it is a third quadrant angle with reference angle 81. When measured from the pole, it is 180 + 81 or 261
OpenStudy (anonymous):
true...
OpenStudy (anonymous):
okay thank you both . ! <3
OpenStudy (anonymous):
and then tan(180+theta)=tanthetha put thetha = 81,,,, u will get d answer
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