Find an angle T on the unit circle such that 90º < T < 360º, tan T = tan U, and M angleU =81º. a. 261° b. 94° c. 99° d. 279°
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a?
261
are you sure? : / what do you think mertsj
well yes i am surre
tan 81 is positive, so our tanT will have to lie in 3rd quadrant to be positive
We know that the tangent of 81 degrees is positive so the angle must be in the third quadrant since the tangent is only positive in Quadrants I and III and it can't be in one since the requirement is that it be greater than 90. So it is a third quadrant angle with reference angle 81. When measured from the pole, it is 180 + 81 or 261
true...
okay thank you both . ! <3
and then tan(180+theta)=tanthetha put thetha = 81,,,, u will get d answer
i get so confused with tan and sin and cos
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