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Mathematics 7 Online
OpenStudy (anonymous):

Find an angle T on the unit circle such that 90º < T < 360º, tan T = tan U, and M angleU =81º. a. 261° b. 94° c. 99° d. 279°

OpenStudy (anonymous):

are you getting the question?

OpenStudy (anonymous):

a?

OpenStudy (anonymous):

261

OpenStudy (anonymous):

are you sure? : / what do you think mertsj

OpenStudy (anonymous):

well yes i am surre

OpenStudy (anonymous):

tan 81 is positive, so our tanT will have to lie in 3rd quadrant to be positive

OpenStudy (mertsj):

We know that the tangent of 81 degrees is positive so the angle must be in the third quadrant since the tangent is only positive in Quadrants I and III and it can't be in one since the requirement is that it be greater than 90. So it is a third quadrant angle with reference angle 81. When measured from the pole, it is 180 + 81 or 261

OpenStudy (anonymous):

true...

OpenStudy (anonymous):

okay thank you both . ! <3

OpenStudy (anonymous):

and then tan(180+theta)=tanthetha put thetha = 81,,,, u will get d answer

OpenStudy (anonymous):

i get so confused with tan and sin and cos

OpenStudy (mertsj):

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