solve the following equations using the method indicated? a. substitution y=3x+4 y=2x+6
first one? What's the question?
what do you mean
the first part of the question doesn't make sense... is it y=3x=4 or y=3x-4?
+ sorry ...
Ok y=3x+4 y=2x+6 2x+6=3x+4 (subsitute y in second equation into first) 2x-3x=4-6 -x=-2 x=2
and y is
y= 3(2) +4 y=6+4 y=10 (subsitute x value in any of two equations)
i really don't get any of this... i suck at math period...
because both equations are equivalent (equal one another) You can replace the first equation into the second... and the y value in the second equation can replace the y value in the first equation... then you have two equaions which you can solve for y... then u get the y value and can alternatively choose either equation to substitute that value to get the x valuel...
sorry i don't get get any of this
awwww. mmmm it's substitution... I had trouble with it at first. Try asking a teacher for more help or anyone here on basic rules for substitution. I'm tired and am off to bed.. Sorry I can;t help you more :(
the thing is my exam is tomorrow :(
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