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Simplify the expression. i^313
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divide 313 by 4 and take the integer remainder
4 goes on to 312 evenly so the remainder is 1 in this case. therefore \(i^{313}=i^1=i\) pattern is \[i^0=1\] \[i^1=i\] \[i^2=-1\] \[i^3=-i\] \[i^4=1\] and so on
ok so when i divided 313 by 4 i got 78.25 would i round that to 8?
it is the remainder you are looking for
and then divide that by 4 again?
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by which i mean the integer remainder. 4 goes in to 313 78 times with a remainder of 1 so you are only concerned with the 1
i.e. \(313=78\times 4+1\) ignore the first part, work only with the 1
So you would divide 78 by 4?
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