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OpenStudy (anonymous):
Is (x-2) and (x+3) factors of x^3+2x^2-5x-6 ?
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OpenStudy (anonymous):
yes they is try either factoring, dividing or replacing \(x\) by 2 and then -3 to see you get zero in both cases
OpenStudy (anonymous):
in fact it is \[(x-2)(x+3)(x+1)\]
OpenStudy (anonymous):
Oh okay thank you. (:
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