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Mathematics 23 Online
OpenStudy (anonymous):

Is (x-2) and (x+3) factors of x^3+2x^2-5x-6 ?

OpenStudy (anonymous):

yes they is try either factoring, dividing or replacing \(x\) by 2 and then -3 to see you get zero in both cases

OpenStudy (anonymous):

in fact it is \[(x-2)(x+3)(x+1)\]

OpenStudy (anonymous):

Oh okay thank you. (:

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