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Mathematics 20 Online
OpenStudy (anonymous):

Use the given line(s) from a random number table to select numbers to use in each problem. Select 2 contestants for a game show out of a pool of 50 46547 17495 25765 11325 14071 61688

OpenStudy (kropot72):

A table of random numbers can be used in many ways. The digits can be taken vertically or horizontally. Any of the five columns can be taken. The last digit can be taken, the next to last digit, pairs of digits in combination, and so on.

OpenStudy (anonymous):

So what do I do with them divide them?

OpenStudy (kropot72):

Each contestant needs to be identified with a number. You then choose one of the many ways to select two numbers from the table.

OpenStudy (anonymous):

This is my choice for answers A. 39, 25 B. 46, 47 C. 4, 6 D. 46, 25 I know C is wrong but I don't know what I am doing

OpenStudy (anonymous):

so say we use 50

OpenStudy (anonymous):

that would be 25 ways

OpenStudy (kropot72):

You need to find which of the choices of answer follows a pattern of selection.

OpenStudy (anonymous):

I still just don't understand what to do probability confuses me

OpenStudy (anonymous):

If I am given a formula I can plug in numbers but word problems and probability confuses me

OpenStudy (kropot72):

This is not a problem regarding probability, combinations or permutations. The task is to see which pair of choices of answer follows a suitable method of selection from the given table of random numbers. You are right in saying that choice C. is not correct.

OpenStudy (kropot72):

Can you find 39 anywhere in the table?

OpenStudy (anonymous):

so do you do something like this 50 46 54 7

OpenStudy (anonymous):

no

OpenStudy (anonymous):

but there is 46, 47, and 25

OpenStudy (anonymous):

so would it be 46,25

OpenStudy (kropot72):

Good. So A. is not a correct choice. Which of the choices 46, 47 and 46, 25 follows a logical method of choosing?

OpenStudy (kropot72):

Yes! 46, 25 choice is correct. Well done:)

OpenStudy (anonymous):

Thank you

OpenStudy (kropot72):

You're welcome :)

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