Question

Cot 15pie/2?

Answer 1

is this is periodic function??

Answer 2

Yes

Answer 3

ok.. Im going to try but im not really sure about this tho?

Answer 4

Ok

Answer 5

I assume you're taking the cotangent of the value 15*pi/2 (as opposed to cot(15 pi) / 2.

The trick you're suppose to recognize is that cotangent is periodic with a period of 2pi. Than means that...
cot(15pi/2) = cot(11pi/2) = cot(7pi/2) = cot(3pi/2)

cot(3pi/2) = cos(3pi/2)/sin(3pi/2)
= 0 / -1
= 0

Soyeah.. im not really sure about this but if someone check this ask them because im not sure if this is right,..XD

Answer 6

Thanks i just needed the steps on how to figure it out this should do it! :)

Answer 7

np XD

Answer 8

\[
\cot(15\pi/2) =\cot( 7\pi + \pi/2) = \cot(\pi/2)=0

\]The period of cot(x) is is \(\pi\)