The length of a rectangle is 5cm more than its width. If its perimeter is 58cm,how do you calculate its dimensions and its area?

Question

anonymous · Answer

width: x
length: x+5
perimeter: 2( x+ x + 5) = 58
find width and length then its area

anonymous · Answer

nphuongsun93 where did you get the 2 from in the calculation of the perimeter?

anonymous · Answer

the perimeter equation is 2 * (width + length)
because there are 2 widths and lengths

anonymous · Answer

L = W + 5

2L + 2W = 58

L + W = 29

(W + 5) + W = 29

2W = 24

Find W and then L from here...

anonymous · Answer

ok lets see if im on the right track so far

anonymous · Answer

i got 12 as the width and 17 as the length

anonymous · Answer

so 12+12+17+17 =58

anonymous · Answer

yep sounds good

anonymous · Answer

Yes, you have done it correctly...

anonymous · Answer

Ok A= l*w
     A= 17 *12
so: A = 204

anonymous · Answer

You have become Star now...

anonymous · Answer

yay :) thank you!