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Mathematics 12 Online
OpenStudy (anonymous):

how do you find the solution of |x + 3| > -2?

OpenStudy (anonymous):

all positive values of x will satisfy dis equation, y?

OpenStudy (anonymous):

|x + 3| > -2? will have 2 solutions

OpenStudy (anonymous):

Yeah it will have two solutions.

OpenStudy (anonymous):

so far all i got were there, x > 1 or x < -5 -5 < x < 1 all real numbers no solution

OpenStudy (anonymous):

mm... im confused. itll be -5

OpenStudy (anonymous):

all real numbers is the answer

OpenStudy (anonymous):

[-3 <= x], [x < -3]

OpenStudy (anonymous):

alright.

OpenStudy (anonymous):

http://www.purplemath.com/modules/absineq.htm

OpenStudy (anonymous):

@timo86m and @srosenfeld0938 , LHS is always positive, nd RHS is always negative, so no matter what value of x we put, the inequality will always hold so answer is all real values

OpenStudy (anonymous):

use the link and [-3 <= x], [x < -3]

OpenStudy (anonymous):

oh okay. i kinda understand it. ha.

OpenStudy (anonymous):

alright ill use the link!

OpenStudy (anonymous):

thanks :)

OpenStudy (anonymous):

good luck

OpenStudy (anonymous):

but it could be all x i read at purple math.

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