Question

find all natural numbers x such that x^2+x+7 is a complete square

Answer 1

x=0 as its undefined

Answer 2

what?

Answer 3

@Diyadiya @Mimi_x3 @ParthKohli @lalaly check out this problem.....

Answer 4

1 is valid....

Answer 5

make that 6

Answer 6

no hw 4...4^2+4+7=27...

Answer 7

yeah 6 is valid...

Answer 8

i think 1,6 are the only numbers but we have to prove that IF its true....

Answer 9

@satellite73 ....?

Answer 10

hint:
\[x^2<x^2+x+7<(x+3)^2\]

Answer 11

hw do we us e this?
@Diyadiya @Mimi_x3 @apoorvk

Answer 12

@FoolForMath

Answer 13

@King
what are the complete squares between x^2 and (x+3)^2

Answer 14

\[x^2<x^2+x+7<(x+3)^2 \\ then \ \ \ x^2+x+7=(x+1)^2 \ \ or \ \ x^2+x+7=(x+2)^2 \]

Answer 15

oh....

Answer 16

nice....:D