Last question! need help on confirming answer!
Justin is using the figure shown below to prove Pythagorean Theorem using triangle similarity. In the given triangle ABC, angle A is 90o and segment AD is perpendicular to segment BC. Which of these could be a step to prove that BC2= BA2 + CA2?
Segment AD : segment CD = segment BD : segment AD, since triangle ADB is similar to triangle CDA. is it this one? Segment BD : segment BA = segment BA : segment CA, since triangle ADB is similar to triangle CDA. Segment BC : segment BA = segment BA : segment BD, since triangle BCA is similar to triangle BAD. Segment BA : segment DA = segment AC : segment BA, since triangle BCA is similar to triangle BAD.
is seg:bd : seg: ba = seg: ba : seg:ca?
BC2= BA2 + CA2 That's the pythagorean's theorem!
yes i've seen where your good on proofs so I asked you for help
I've never proved this theorem by using triangles :| Lemme check.
Yes, your choice is right :)
YES! thanks
Then you have to cross multiply the ratios, add them up and simplify :)
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