Question

Solving with the interval [0,2pi)
1+sin(theta)=1/2

Answer 1

x= (7/6)pi, and x= (11/6)pi ?

Answer 2

\[\sin \theta=(1/2)-1\]
\[\sin \theta=-1/2\]

If you have the interval [0,2pi], then you are looking for an angle (or angles) between 0 and 2pi whose sin equals -1/2

Answer 3

yes, that would be the answer for your question.

Answer 4

Ah thanks