Question

For some reason this confuses me.
Find the zeros of the function by rewriting it in intercept form.

Answer 1

\[y=x^2+8x+15\]

Answer 2

zeros of the function means , where the graph cross x axis. That means points of the graph where y coordinate is equal to 0

Answer 3

I know, but I don't remember and intercept form for quadratics.

Answer 4

Just put y=0 in the equation to find x-intercept
\[x ^{2}+8x+15=0\]

Answer 5

factorising: (x+3)(x+5)=0
so x=-3 and x=-5 are the zeros