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so confused..."write the equation of a line, in standard form, passing through the point A(-2,7) and parallel to the line whose equation is y=2x-3" ..help please??
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parallel lines have the same slope the slope of \(y=mx+b\) is \(m\) and therefore the slope of \(y=2x-3\) is 2
now you use the point - slope formula \[y=y_1=m(x-x_1)\] with \(m=2, x_1=-2, y_1=7\) make the real number replacements and see what you get
typo there, should have been \[y-y_1=m(x-x_1)\]
you get \[y-7=2(x-(-2))\] or \[y-7=2(x+2)\]
thank you
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