Question

-(tan^2 -sin^2 -cos^2-sec^2)=

Answer 1

\[-\tan^2x + \sin^2x + \cos^2x +\sec^2x\]

\[\sin^2x + \cos^2x +\sec^2x - \tan^2x\]

Remember:

\[\sec^2x - tanx = 1\]

\[\sin^2x + \cos^2x = 1\]

Use these formulae and get the answer...

Answer 2

so answer would be 2

Answer 3

You are right..

Answer 4

There it will come tan^2x in place of tanx...