A cylindrical vase has a diameter of 4 inches. At the bottom of the vase, there are 6 marbles, each of diameter 2 inches. The vase is filled with water up to a height of 8 inches.

Question

A cylindrical vase has a diameter of 4 inches.  At the bottom of the vase, there are 6 marbles, each of diameter 2 inches. The vase is filled with water up to a height of 8 inches.

anonymous · Answer

then what?

anonymous · Answer

What is the volume of water in the vase?

anonymous · Answer

what is the total volume of marbles?

anonymous · Answer

yes

anonymous · Answer

total filled volume of vase is 
$$V _{tot}=\frac{\pi D^2}{4} H=\frac{16\pi}{4}*8=32\pi$$

anonymous · Answer

$$V_{marbles}=6*\frac{4}{3} \pi r^3 \ \ \ \ r=d/2=2/2=1 \ then \ \ \  V_{marbles}=6*\frac{4}{3} \pi =8\pi$$

anonymous · Answer

$$V_{water}=V_{tot}V_{marbles}=32\pi-8\pi=24\pi$$

anonymous · Answer

you just made this really confusing i thought it was
πr2h

anonymous · Answer

πr2h is total volume not the volume of water

anonymous · Answer

***V(water)=V(Total)-V(marbles)