Question

Simplify radical expression..

square root 10/81

Answer 1

\[\sqrt{\frac {10}{81}} =\sqrt{\frac {2 \times 5}{3 \times 3}} = \frac 1 3 \sqrt{2 \times 5} = \frac{\sqrt{10}}3\]

Answer 2

thanks! what about this one \[\sqrt{6} + 2 \sqrt{6}\]

Answer 3

@apoorvk \(\sqrt{81} \ne 3\)

Answer 4

Omg thanks Parth, I realised it yeah... Sorry @zebra11, a bit of a correction,
\(\sqrt{81} = \sqrt{9 \times 9} = 9\)

can you apply this correction by your yourself?

Answer 5

Yeah I got it.. what about the \[\sqrt{6} + 2 \sqrt {6}\]

Answer 6

hmm, \(\sqrt6\) is common to both terms, so if you take it out as common, you'd get:

\((1+2)\sqrt6 = 3\sqrt6 \)

helps?

Answer 7

yes. thanks!

Answer 8

no worries..