Question

For the equation x2 + 3x + j = 0, find all the values of j such that the equation has two real number solutions. Show your work

Answer 1

for 2 real solutions the discriminant b^2 - 4ac > 0
here it = 3^2 - 4 *1*j = 9 - 4j
solve the inequality 9 - 4j = 0
to find required values of j

Answer 2

the a, b and c of the discriminant formula are from the general equation of quadratic

ax^2 + bx + c = 0

Answer 3

ax^2 + bx + c = 0 compare with
x^2 + 3x + j = 0

a=1, b = 3 and c = j

Answer 4

can you solve 9 - 4j > 0 ?