Question

(3x^2a-4y^a z^3a)^2

Answer 1

\[(3x ^{2}2a-4y ^{a}z ^{3}a)^{2}\] As I read correct?

Answer 2

yes

Answer 3

well that translates to \[(3x ^{2}2a-4y ^{a}z ^{3}a)(3x ^{2}2a-4y ^{a}z ^{3}a)\]

Answer 4

Now use FOIL or First Outers Inners Lasts multiplying them

Answer 5

I never really learned the foil thing

Answer 6

Well Firsts means \[3x ^{2}2a \times 3x ^{2}2a\]

Answer 7

now do you kind of get the idea?

Answer 8

Multiply the beginnings, the first term of the equation and last term, the terms in the middle and the last terms