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OpenStudy (anonymous):
9x^2+4x=0
x(9x+4)=0
either
x=0
or, 9x+4=0
OpenStudy (anonymous):
would it be (3x+2)(3x-2) do that is 6x-6x=0?
OpenStudy (anonymous):
I'm not sure your answer is correct
OpenStudy (anonymous):
we can not factorize it like this because
a^2-b^2=(a+b)(a-b)
OpenStudy (anonymous):
if the question is like
9x^2-4
then we do this
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OpenStudy (anonymous):
but we would multiply the inner product and then the outer product and then add together. In my example ... I know that is one of the ways on my homework. I was just unsure.
OpenStudy (anonymous):
in the question we see that there is "x" common so, we first take out "x"
9x^2+4x = x(9x+4)
OpenStudy (anonymous):
so, the factorize form of 9x^2+4x is x(9x+4)
OpenStudy (anonymous):
yes that's right sorry read it wrong
OpenStudy (anonymous):
:)
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OpenStudy (anonymous):
now either x=0 or , 9x+4=0
so, x=0 is one of the answer
and we solve 9x+4 =0 for other answer
OpenStudy (campbell_st):
the only common factor is x
so you have x(9x + 4) = 0
then x = 0 or -4/9 as the solutions to the equations