Question

Find three consecutive even integers such that the first times the third is 2 greater the 5 times than the second?

Answer 1

\[a\times(a+4)+2=5(a+2)\]

Answer 2

let the even number be x......(x),(x+2),(x+4) are consecutive even numbers

first times third =(x)(x+4)
5 times second is =(x+2)*5

according to the condition
(x)(x+4)+2=5(x+2)

re=read the condition and u'll understand....solve for x

Answer 3

The Prophet and UnkleRhaukus thank you very much. :D

Answer 4

the first of the consecutive numbers is \(x \text{ or } a\)
the second is \(x +2\text{ or } a+2\)
the third is...

Answer 5

I got it.

x(x+4)=2+5(x+2)
=x^2+4x=2+5x+10
=x^2+4x=12+5x
=x^2-x-12=0
=(x-4)(x+3)

Answer 6

ah, so there are two sets of solutions,

only one of these makes a sensible answer