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OpenStudy (anonymous):
Find two numbers with a sum of 20 and a difference of 14.
A. 4 and 18
B. –3 and –17
C. 2 and 16
D. 3 and 17
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Parth (parthkohli):
\( \color{Black}{\Rightarrow a + b = 20}\)
\( \color{Black}{\Rightarrow a - b = 14}\)
Parth (parthkohli):
Solve this system.
Parth (parthkohli):
Try solving it by elimination
OpenStudy (anonymous):
Why dont you just and try to use the solutions and see which yields true?
This just comes accross as lazy...
OpenStudy (anonymous):
Use simultaneous equations:
a+b=20
a-b=14
take them away from eachother:
2b=6
b=3
substitute into one of the equations:
a+3=20
a=17
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OpenStudy (anonymous):
From the sum being 20 alone you can tell the answer is D. Literally zero effort and all I did was sum two numbers for each possibility.
Parth (parthkohli):
The main thing is learning the algebraic solutions. That is better.
OpenStudy (anonymous):
the answer is D
OpenStudy (anonymous):
correct :)
OpenStudy (anonymous):
thank you
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OpenStudy (anonymous):
nor problem :)
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