Question

Solve.
2x^2+x-1=9

Answer 1

oh !
please explain the steps heh.
thanks !

Answer 2

First you have to subtract 9 from both sides to make it into the form of quadratic equation

that is: \( ax^2 + bx + c \)

Answer 3

can you do that?

Answer 4

so it's 2x^2+x-10?

Answer 5

Exactly ,Don't forget " =0 "

2x^2+x-10=0

Answer 6

haha okay :)

Answer 7

do you know to factor it now?

Answer 8

(2x+5)(x-2)

Answer 9

Very good!

again you forgot the zero :D

Answer 10

LOL.

Answer 11

so it is ?

Answer 12

well, this is the part I don't know haha. I only know how to factor.. but solve I dunno? :/

Answer 13

Its easy


(2x+5)(x-2) =0

so
2x+5 =0 & x-2 =0

can you do now? and tell me what you got!

Answer 14

ohhh!!
uhm, first x = -2.5 x=2

Answer 15

well i see you made a little mistake while factoring its (x+2) not (x-2)

Answer 16

uhh wait it's not though.? cause if you factor it it becomes the top. and if you did a plus and plus, the toptop expression would be all positave

Answer 17

I think the answer is (2, -5/2)
it's in the multiple choices. :/ idk

Answer 18

2x^2+x-10=0
2x^2+5x-4x-10=0

x(2x+5)-2(2x+5) =0
(x-2) (2x+5) =0
x=2 x= 5/2


Sorry for the confusion, you're absolutely right!

Answer 19

* x =-5/2

Answer 20

Haha thank you so much!
:D

Answer 21

Anytime :)