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Mathematics 26 Online
OpenStudy (anonymous):

can anybody help me in differentiation. . ??

OpenStudy (diyadiya):

Post you question, I'll try :)

OpenStudy (diyadiya):

*your

OpenStudy (anonymous):

sin(3X+5)

OpenStudy (diyadiya):

\[\frac{d}{dx} \sin(3x+5)\] for this you have to use the chain rule. By the way do you know what is \[\frac{d}{dx} sinx = ?\]

OpenStudy (anonymous):

cosx

OpenStudy (diyadiya):

Yes \[\frac{d}{dx}\sin(3x+5) = \cos(3x+5) ~ \frac{d}{dx}(3x+5)\] do you know what is \[\frac{d}{dx}(3x+5)\] ??

OpenStudy (anonymous):

3cos(3x+5)

OpenStudy (diyadiya):

Right!!!

OpenStudy (anonymous):

ohhh. . thank you. . by the way You doing what. . . You just great in maths

OpenStudy (diyadiya):

Haha you're Welcome! I completed 12th grade! Not so great in Maths! :D

OpenStudy (anonymous):

:)

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