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can anybody help me in differentiation. . ??
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Post you question, I'll try :)
*your
sin(3X+5)
\[\frac{d}{dx} \sin(3x+5)\] for this you have to use the chain rule. By the way do you know what is \[\frac{d}{dx} sinx = ?\]
cosx
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Yes \[\frac{d}{dx}\sin(3x+5) = \cos(3x+5) ~ \frac{d}{dx}(3x+5)\] do you know what is \[\frac{d}{dx}(3x+5)\] ??
3cos(3x+5)
Right!!!
ohhh. . thank you. . by the way You doing what. . . You just great in maths
Haha you're Welcome! I completed 12th grade! Not so great in Maths! :D
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