Question

A small toy company makes two types of toys: dolls and toy cars. The expense to make a toy car is $5. The expense to make a doll is $7. The company spends $780 a day making toys. They also make 20 toy cars fewer than twice the number of dolls they make. Construct a system of equations that describes this situation.

Answer 1

@Hero needs to help.

Answer 2

Or @jackellyn (:

Answer 3

let c be toy cars
d be dolls

The expense to make a toy car is $5. The expense to make a doll is $7. The company spends $780 a day making toys

780 = -5c -7d

They also make 20 toy cars fewer than twice the number of dolls they make:
c=2d-20

So the system of equations is:
780 = -5c -7d
c=2d-20

Answer 4

Is that answer right @Loujoelou

Answer 5

I'm just wondering, @jackellyn why wouldn't the first equation be 5c+7t=780?

Answer 6

@Loujoelou , minor error I meant to put
-780 = -5c - 7d

which is equivalent to

780 = 5c +7d

because they are losing money in all three aspects (spend, expense, expense).